Australia&aposs Wade Ormsby will take a slender one-shot lead into the final round of the India Open on the Asian Tour. Ormsby carded a two-over 74 on Saturday, but it was good enough to maintain the outright lead as other players around him slipped up. The Australian sits at the top of proceedings at eight-under overall, with Singapore&aposs Chih Bing Lam his closest challenger at minus seven. Another two shots back, in a tie for third place, are local hope Shiv Kapur and Thailand&aposs Boonchu Ruangkit, while India&aposs Jyoti Randhawa is a further stroke adrift in outright fifth. Matthew Stieger is the only other Australian in contention, with the youngster seven shots off the pace in a tie for 10th place.